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6 lines
296 B
Markdown
6 lines
296 B
Markdown
#math #stats
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the probability of both events happening
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$$P(A\cap B) = P(A)P(B|A)$$
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since if B were to be dependent upon A, we don't want to essentialy count the probability of A happening twice, so we have to seperate it with $P(B|A)$
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if both A and B are **independent**,
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$$P(A\cap B) = P(A)P(B)$$ |