mirror of
https://github.com/jackyzha0/quartz.git
synced 2025-12-24 13:24:05 -06:00
296 B
296 B
#math #stats the probability of both events happening
P(A\cap B) = P(A)P(B|A)since if B were to be dependent upon A, we don't want to essentialy count the probability of A happening twice, so we have to seperate it with $P(B|A)$ if both A and B are independent,
P(A\cap B) = P(A)P(B)