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#math/calculus
$\epsilon$=tiniest little value N = a possible findable number n = index in the sequence. L = a possible findable limit
convergence (for sequences)
for all \epsilon>0 we can find N:
n>N ------- |L-a_n|<\epsilon
divergence (for sequences)
for all M we can find N such that (st):
n>N ------ $a_n>M$
The sequence constantly grows in a direction.
Or, it can oscillate! sin(x) does not converge, so it's divergent.
test for divergence or convergence of series
from sympy import *
x=symbols('x')
series = Sum(1/(6 + exp(-x)), (x, 1, oo))
series.is_convergent()
- test for divergence
- break it into parts
- check if geometric
- telescoping
- MCT monotone_and_bounded? Integral bigger converges? Series converges
- Integral test. If the integral starting from 1 converges, it converges. For the Integral test, the function must be:
- !More tests for convergence#Direct Comparison Test
- !More tests for convergence#Limit Comparison Test
- !Alternating Series Test
- !Ratio test
- Root Test !Pasted image 20220526191532.png
